For the following reaction,CaCl23322Molar mass of CaCl23Molar mass of CaCO3The CaCl2222233(aq) + 2NaHCO(aq) ? CaCO(s) + HO(l) + CO(g) + 2NaCl(aq) = 110.98 g/molMolar mass of NaHCO = 84.007 g/mol = 100.09 g/mol used in this experiment exist as a dihydrate, CaCl•2HO. If 1.00 g of CaCl•2HO reacted with an excess amount of NaHCO, how many grams of solid CaCO should precipitate out? Science Chemistry CHEM 022